Chapter 84

Chapter 8 Exercise D
1. Solution: By Exercise 11 in section 8B the characteristic polynomial is $z^4$ and by 8.46 this is...
Chapter 8 Exercise C
1. Solution: Because $$ 4 = \operatorname{dim} \mathbb{C}^4 = \operatorname{dim} G(3, T) + \operator...
Chapter 8 Exercise B
1. Solution: By 8.21 (a), $V = G(0, N)$. Since $G(0, N) = \operatorname{null} N^{\operatorname{dim} ...
Chapter 8 Exercise A
1. Solution: Since $$ T^2(w, z) = T(z, 0) = (0, 0), $$ it follows that $G(0, T) = V$. Therefore ever...